How can I dump Python objects without tags using PyYAML? I have such class:
class Monster(yaml.YAMLObject):
yaml_tag = u'!Monster'
def __init__(self, name, hp, ac, attacks):
self.name = name
self.hp = hp
self.ac = ac
self.attacks = attacks
Then I try to dump:
print(yaml.dump(Monster(name='Cave lizard', hp=[3,6], ac=16, attacks=['BITE','HURT'])))
And got the result:
!Monster
ac: 16
attacks: [BITE, HURT]
hp: [3, 6]
name: Cave lizard
But the desired result is:
ac: 16
attacks: [BITE, HURT]
hp: [3, 6]
name: Cave lizard
How can I get this?
Since you don't want to emit the tags, you should change the method that does that into a no-op:
import yaml
import sys
class Monster(yaml.YAMLObject):
yaml_tag = u'!Monster'
def __init__(self, name, hp, ac, attacks):
self.name = name
self.hp = hp
self.ac = ac
self.attacks = attacks
def noop(self, *args, **kw):
pass
yaml.emitter.Emitter.process_tag = noop
yaml.dump([
Monster(name='Cave lizard', hp=[3,6], ac=16, attacks=['BITE','HURT']),
Monster(name='Sméagol', hp=400, ac=14, attacks=['TOUCH','EAT-GOLD']),
], sys.stdout, allow_unicode=True)
which gives:
- ac: 16
attacks: [BITE, HURT]
hp: [3, 6]
name: Cave lizard
- ac: 14
attacks: [TOUCH, EAT-GOLD]
hp: 400
name: Sméagol
Please note that using print(yaml.dump())
is inefficient in time and memory. PyYAML has a streaming interface, so you should directly use it instead of streaming to a buffer and then streaming the buffer using print()
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