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Pythonic way to set sort order?

Tags:

python

I have a collection on objects that I need to assign a random order. I wrote a pretty dumb java style loop to do it, but what is a fancier pythonic way to achieve the same?

from random import shuffle

class pair(object):
    def __init__(self, name):
        self.name = name
        self.order = 0
    def __repr__(self):
        return self.name + " order: " + str(self.order)

test =[pair('a'),pair('b'),pair('c'),pair('d')]
print(test)
#shuffle the list
shuffle(test)
i = 1
#this is what i want to replace <------
for t in test:
    t.order=i
    i+=1

print(test)

Sample output:

>>>[a order: 0, b order: 0, c order: 0, d order: 0]
>>>[c order: 1, a order: 2, d order: 3, b order: 4]
like image 733
Nix Avatar asked Jul 10 '26 20:07

Nix


1 Answers

This isn't a lot simpler than yours, but it's perhaps a little bit neater:

for i, t in enumerate(test):
    t.order = i
like image 135
RichieHindle Avatar answered Jul 12 '26 11:07

RichieHindle