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How is Python's with keyword expressed in a lambda function? Consider the following:
def cat (filename):
with open(filename, 'r') as f:
return f.read()
A failed attempt at a lambda implementation:
cat = lambda filename: with open(filename, 'r') as f: return f.read()
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What are lambda functions in Python? In Python, an anonymous function is a function that is defined without a name. While normal functions are defined using the def keyword in Python, anonymous functions are defined using the lambda keyword. Hence, anonymous functions are also called lambda functions.
In particular, a lambda function has the following characteristics: It can only contain expressions and can't include statements in its body. It is written as a single line of execution.
In Python, a lambda function is a single-line function declared with no name, which can have any number of arguments, but it can only have one expression. Such a function is capable of behaving similarly to a regular function declared using the Python's def keyword.
lambda_form ::= "lambda" [parameter_list]: expression
You can't, with is a statement, and lambda only returns expressions.
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