Python: using for loops to output ASCII table

Question

For a tutorial, I need to output the following table on python using nested for loops:

asc: 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47
chr: 0   1  2  3  4  5  6  7  8  9  :  ;  <  =  >  ?
asc: 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63
chr: @   A  B  C  D  E  F  G  H  I  J  K  L  M  N  O
asc: 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79
chr:  P  Q  R  S  T  U  V  W  X  Y  Z  [  \  ]  ^  _
asc: 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95
chr:  `  a  b  c    d  e   f   g   h   i   j   k   l   m   n   o
asc: 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111
chr:  p  q  r  s   t   u   v   w   x   y   z   {   |   }   ~
asc: 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127'''

Since this is the beginners class we have not learned def. This question has been answered in previous posts but the answers use def and I cannot

So far my code looks like this:

X=0
for Rows in range(0,12,2):
   X=X+1
   if Rows%2==0:
      print('chr:',end="")
      for chrColumns in range (32,48):
        print('%4s'%chr(chrColumns+(X-1)*16), end="")
   print()
   if Rows%2==1:
      print('asc:',end="")
      for ascColumns in range (16,32):
      print(ascColumns+(X-1)*16,end="")
   print()

I cannot find a way for the "chr:" rows to alternate with "asc:" rows. Please help me

Answer 1

How about something like this?

for c in range(32, 128, 16):
    #print chr line
    for c1 in range(c, c+16):
        # print chr
    #print asc line
    for c2 in range(c, c+16):
        # print asc