Python unescape URL

Question

I have got a url in this form - http:\\/\\/en.wikipedia.org\\/wiki\\/The_Truman_Show. How can I make it normal url. I have tried using urllib.unquote without much success.

I can always use regular expressions or some simple string replace stuff. But I believe that there is a better way to handle this...

Answer 1

urllib.unquote is for replacing %xx escape codes in URLs with the characters they represent. It won't be useful for this.

Your "simple string replace stuff" is probably the best solution.