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When I try to execute a python program from command line, it gives the following error. These errors do not cause any problem to my ouput. I dont want it to be displayed in the commandline
Traceback (most recent call last):
File "test.py", line 88, in <module>
p.feed(ht)
File "/usr/lib/python2.5/HTMLParser.py", line 108, in feed
self.goahead(0)
File "/usr/lib/python2.5/HTMLParser.py", line 148, in goahead
k = self.parse_starttag(i)
File "/usr/lib/python2.5/HTMLParser.py", line 226, in parse_starttag
endpos = self.check_for_whole_start_tag(i)
File "/usr/lib/python2.5/HTMLParser.py", line 301, in check_for_whole_start_tag
self.error("malformed start tag")
File "/usr/lib/python2.5/HTMLParser.py", line 115, in error
raise HTMLParseError(message, self.getpos())
HTMLParser.HTMLParseError: malformed start tag, at line 319, column 25
How could I suppress the errors?
575
Using Try Exceptblock to catch the ZeroDivisionError exception and ignore it. In the above code, we catch the ZeroDivisionError exception and use pass to ignore it. So, when this exception happens, nothing will be thrown and the program will just keep running by ignoring the zero number.
The try block lets you test a block of code for errors. The except block lets you handle the error. The else block lets you execute code when there is no error. The finally block lets you execute code, regardless of the result of the try- and except blocks.
When an exception is raised, no further statements in the current block of code are executed. Unless the exception is handled (described below), the interpreter will return directly to the interactive read-eval-print loop, or terminate entirely if Python was started with a file argument.
Doesn't catching HTMLParseError work for you? If test.py is the name of your python file, it's propagated up to there, so it should.
Here's an example how to suppress such an error. You might want to tweak it a bit to match your code.
try:
# Put parsing code here
except HTMLParseError:
pass
You can also just suppress the error message by redirecting stderr to null, like Ignacio suggested. To do it in code, you can just write the following:
import sys
class DevNull:
def write(self, msg):
pass
sys.stderr = DevNull()
However, this is probably not be what you want, because from your error it looks like the script execution is stopped, and you probably want it to be continued.
187
Redirect stderr to /dev/null.
python somescript.py 2> /dev/null
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