I'm using Python standard logging module with custom formatter where I limit length of some fields. It uses standard %
Python operator.
I can apply limit for percent-formatted string like this (this limits length to 10 chars):
>>> "%.10s" % "Lorem Ipsum"
'Lorem Ipsu'
Is it possible to trim it from the beginning, so the output is 'orem Ipsum'
(without manipulating right-side argument)?
Use syntax string[x:y] to slice a string starting from index x up to but not including the character at index y. If you want only to cut the string to length in python use only string[: length].
use this: while True: answer = input("What's up, doc? ") if len(answer) >= 10: print("Too much info - keep it shorter!
Python's % formatting comes from C's printf.
Note that the .
indicates precision for a float. That it works on a string is a mere side effect, and unfortunately, there is no provision in the string formatting specification to accommodate stripping a string from the left to a fixed max width.
Therefore if you must strip a string to a fixed width from the end, I recommend to slice from a negative index. This operation is robust, and won't fail if the string is less than 10 chars.
>>> up_to_last_10_slice = slice(-10, None)
>>> 'Lorem Ipsum'[up_to_last_10_slice]
'orem Ipsum'
>>> 'Ipsum'[up_to_last_10_slice]
'Ipsum'
str.format
also no helpstr.format
is of no help here, the width is a minimum width:
>>> '{lorem:>10}'.format(lorem='Lorem Ipsum')
'Lorem Ipsum'
>>> '{lorem:*>10}'.format(lorem='Lorem')
'*****Lorem'
(The asterisk, "*
", is the fill character.)
This can easily be done through slicing, so you do not require any string format manipulation to do your JOB
>>> "Lorem Ipsum"[-10:]
'orem Ipsum'
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