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Is there a format option such that
>>> '%.1(format)'%2.85
gives '2.8'?
In Python 2.7, 'f' format rounds to nearest
>>> "{:.0f}".format(2.85)
'3'
>>> "%.0f"%2.85
'3'
>>> "%.1f"%2.85
'2.9'
>>> "%i"%2.85
'2'
750
Python's round() function requires two arguments. First is the number to be rounded. Second argument decides the number of decimal places to which it is rounded. To round the number to 2 decimals, give second argument as 2.
Float#truncate() is a float class method which return a truncated value rounded to ndigits decimal digits precision.
Use string slicing to truncate a string Use the syntax string[x:y] to slice a string starting from index x up to but not including the character at index y . If index x is not specified it defaults to zero.
No, there is not. Have a look at the documentation for a complete list of supported floating point format specifiers.
You need to round in your code instead
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