I have a string field : "[Paris, Marseille, Pays-Bas]". I want to convert this string to a list of strings.
For now I have the following function :
def stringToList(string):
string = string[1:len(string)-1]
try:
if len(string) != 0:
tempList = string.split(", ")
newList = list(map(lambda x: str(x), tempList))
else:
newList = []
except:
newList = [-9999]
return(newList)
I want to know if there is a simpler or a shorter method with the same results.
I could use ast.literal_eval() if my input data were of type int. But in my case, it does not work.
Thank you
Worth to know:
import re
string = "[Paris, Marseille, Pays-Bas]"
founds = re.findall('[\-A-Za-z]+', string)
It will find all that consist at least one of of -, A-Z, and a-z.
One pros is that it can work with less-neat strings like:
string2 = " [ Paris, Marseille , Pays-Bas ] "
string3 = " [ Paris , Marseille , Pays-Bas ] "
This splits it into a list of strings:
'[Paris, Marseille, Pays-Bas]'.strip('[]').split(', ')
# ['Paris', 'Marseille', 'Pays-Bas']
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With