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python Socket.IO client for sending broadcast messages to TornadIO2 server

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I am building a realtime web application. I want to be able to send broadcast messages from the server-side implementation of my python application.

Here is the setup:

  • socketio.js on the client-side
  • TornadIO2 server as Socket.IO server
  • python on the server-side (Django framework)

I can succesfully send socket.io messages from the client to the server. The server handles these and can send a response. In the following i will describe how i did that.

Current Setup and Code

First, we need to define a Connection which handles socket.io events:

class BaseConnection(tornadio2.SocketConnection):
    def on_message(self, message):
        pass

    # will be run if client uses socket.emit('connect', username)
    @event
    def connect(self, username):
        # send answer to client which will be handled by socket.on('log', function)
        self.emit('log', 'hello ' + username)

Starting the server is done by a Django management custom method:

class Command(BaseCommand):
    args = ''
    help = 'Starts the TornadIO2 server for handling socket.io connections'

    def handle(self, *args, **kwargs):
        autoreload.main(self.run, args, kwargs)

    def run(self, *args, **kwargs):
        port = settings.SOCKETIO_PORT

        router = tornadio2.TornadioRouter(BaseConnection)

        application = tornado.web.Application(
            router.urls,
            socket_io_port = port
        )

        print 'Starting socket.io server on port %s' % port
        server = SocketServer(application)

Very well, the server runs now. Let's add the client code:

<script type="text/javascript">    
    var sio = io.connect('localhost:9000');

    sio.on('connect', function(data) {
        console.log('connected');
        sio.emit('connect', '{{ user.username }}');
    });

    sio.on('log', function(data) {
        console.log("log: " + data);
    });
</script>

Obviously, {{ user.username }} will be replaced by the username of the currently logged in user, in this example the username is "alp".

Now, every time the page gets refreshed, the console output is:

connected
log: hello alp

Therefore, invoking messages and sending responses works. But now comes the tricky part.

Problems

The response "hello alp" is sent only to the invoker of the socket.io message. I want to broadcast a message to all connected clients, so that they can be informed in realtime if a new user joins the party (for example in a chat application).

So, here are my questions:

  1. How can i send a broadcast message to all connected clients?

  2. How can i send a broadcast message to multiple connected clients that are subscribed on a specific channel?

  3. How can i send a broadcast message anywhere in my python code (outside of the BaseConnection class)? Would this require some sort of Socket.IO client for python or is this builtin with TornadIO2?

All these broadcasts should be done in a reliable way, so i guess websockets are the best choice. But i am open to all good solutions.

like image 710
Alp Avatar asked Jun 08 '12 14:06

Alp


1 Answers

I've recently written a very similar application on a similar setup, so I do have several insights.

The proper way of doing what you need is to have a pub-sub backend. There's only so much you can do with simple ConnectionHandlers. Eventually, handling class-level sets of connections starts to get ugly (not to mention buggy).

Ideally, you'd want to use something like Redis, with async bindings to tornado (check out brukva). That way you don't have to mess with registering clients to specific channels - Redis has all that out of the box.

Essentially, you have something like this:

class ConnectionHandler(SockJSConnection):
    def __init__(self, *args, **kwargs):
        super(ConnectionHandler, self).__init__(*args, **kwargs)
        self.client = brukva.Client()
        self.client.connect()
        self.client.subscribe('some_channel')

    def on_open(self, info):
        self.client.listen(self.on_chan_message)

    def on_message(self, msg):
        # this is a message broadcast from the client
        # handle it as necessary (this implementation ignores them)
        pass

    def on_chan_message(self, msg):
        # this is a message received from redis
        # send it to the client
        self.send(msg.body)

    def on_close(self):
        self.client.unsubscribe('text_stream')
        self.client.disconnect()

Note that I used sockjs-tornado which I found to be much more stable than socket.io.

Anyway, once you have this sort of setup, sending messages from any other client (such as Django, in your case) is as easy as opening a Redis connection (redis-py is a safe bet) and publishing a message:

import redis
r = redis.Redis()
r.publish('text_channel', 'oh hai!')

This answer turned out pretty long, so I went the extra mile and made a blog post out of it: http://blog.y3xz.com/blog/2012/06/08/a-modern-python-stack-for-a-real-time-web-application/

like image 108
Yuval Adam Avatar answered Oct 21 '22 05:10

Yuval Adam