I would like to send email through a proxy.
My current implementation is as follows:
I connect to the smtp server with authentication. After I've successfully logged in, I send an email. It works fine but when I look at the email header I can see my host name. I would like to tunnel it through a proxy instead.
Any help will be highly appreciated.
To use a proxy in Python, first import the requests package. Next create a proxies dictionary that defines the HTTP and HTTPS connections. This variable should be a dictionary that maps a protocol to the proxy URL. Additionally, make a url variable set to the webpage you're scraping from.
The smtplib module defines an SMTP client session object that can be used to send mail to any internet machine with an SMTP or ESMTP listener daemon. For details of SMTP and ESMTP operation, consult RFC 821 (Simple Mail Transfer Protocol) and RFC 1869 (SMTP Service Extensions). Availability: not Emscripten, not WASI.
Python comes with the built-in smtplib module for sending emails using the Simple Mail Transfer Protocol (SMTP). smtplib uses the RFC 821 protocol for SMTP. The examples in this tutorial will use the Gmail SMTP server to send emails, but the same principles apply to other email services.
Use SocksiPy:
import smtplib
import socks
#'proxy_port' should be an integer
#'PROXY_TYPE_SOCKS4' can be replaced to HTTP or PROXY_TYPE_SOCKS5
socks.setdefaultproxy(socks.PROXY_TYPE_SOCKS4, proxy_host, proxy_port)
socks.wrapmodule(smtplib)
smtp = smtplib.SMTP()
...
I had a similar problem yesterday, this is the code I wrote to solve the problem. It invisibly allows you to use all of the smtp methods via proxy.
#!/usr/bin/env python
# -*- coding: utf-8 -*-
#
# smtprox.py
# Shouts to suidrewt
#
# ############################################# #
# This module allows Proxy support in MailFux. #
# Shouts to Betrayed for telling me about #
# http CONNECT #
# ############################################# #
import smtplib
import socket
def recvline(sock):
stop = 0
line = ''
while True:
i = sock.recv(1)
if i == '\n': stop = 1
line += i
if stop == 1:
break
return line
class ProxSMTP( smtplib.SMTP ):
def __init__(self, host='', port=0, p_address='',p_port=0, local_hostname=None,
timeout=socket._GLOBAL_DEFAULT_TIMEOUT):
"""Initialize a new instance.
If specified, `host' is the name of the remote host to which to
connect. If specified, `port' specifies the port to which to connect.
By default, smtplib.SMTP_PORT is used. An SMTPConnectError is raised
if the specified `host' doesn't respond correctly. If specified,
`local_hostname` is used as the FQDN of the local host. By default,
the local hostname is found using socket.getfqdn().
"""
self.p_address = p_address
self.p_port = p_port
self.timeout = timeout
self.esmtp_features = {}
self.default_port = smtplib.SMTP_PORT
if host:
(code, msg) = self.connect(host, port)
if code != 220:
raise SMTPConnectError(code, msg)
if local_hostname is not None:
self.local_hostname = local_hostname
else:
# RFC 2821 says we should use the fqdn in the EHLO/HELO verb, and
# if that can't be calculated, that we should use a domain literal
# instead (essentially an encoded IP address like [A.B.C.D]).
fqdn = socket.getfqdn()
if '.' in fqdn:
self.local_hostname = fqdn
else:
# We can't find an fqdn hostname, so use a domain literal
addr = '127.0.0.1'
try:
addr = socket.gethostbyname(socket.gethostname())
except socket.gaierror:
pass
self.local_hostname = '[%s]' % addr
smtplib.SMTP.__init__(self)
def _get_socket(self, port, host, timeout):
# This makes it simpler for SMTP_SSL to use the SMTP connect code
# and just alter the socket connection bit.
if self.debuglevel > 0: print>>stderr, 'connect:', (host, port)
new_socket = socket.create_connection((self.p_address,self.p_port), timeout)
new_socket.sendall("CONNECT {0}:{1} HTTP/1.1\r\n\r\n".format(port,host))
for x in xrange(2): recvline(new_socket)
return new_socket
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