Python: script's directory

Question

I was looking for a solution, but have not found what I need.

Script path: /dir/to/script/script.py or C:\dir\script.py

Excepted result:

$ ./script.py
output: /dir/to/script
$ cd .. && ./script/script.py
output: /dir/to/script

Is there any function in os module or something?

---

I mixed solutions and write:

print os.path.abspath(os.path.dirname(__file__))

But it's ugly. Is there better way?

Answer 1

os.path.realpath will give you the result:

os.path.dirname(os.path.realpath(__file__))