Python scheduling a job starting every weekday and running every hour

Question

I currently have a sample code defined as:

import schedule
import time

def job(t):
    print ("I'm working...", t)
    return

schedule.every().day.at("01:00").do(job,'It is 01:00')

while True:
    schedule.run_pending()
    time.sleep(60) # wait one minute

I am looking to however run the code every hour on weekdays from 9AM to 4PM. i.e. every day Monday through Friday I want to run the code at 9AM, 10AM, ..., 3PM, 4PM.

Reading the documentation for schedule it seems that I can run the code individually Monday through Friday but not only weekday between two specified times.

Also, shouldn't the following time.sleep(60) make the code run perpetually?

Answer 1

The only way it worked for me is this:

import schedule
import datetime
import time

nowtime = str(datetime.datetime.now())

def job(t):
    print("I'm working...", str(datetime.datetime.now()), t)

for i in ["06:00", "09:00", "12:00", "15:00", "18:00"]:
    schedule.every().monday.at(i).do(job, i)
    schedule.every().tuesday.at(i).do(job, i)
    schedule.every().wednesday.at(i).do(job, i)
    schedule.every().thursday.at(i).do(job, i)
    schedule.every().friday.at(i).do(job, i)

while True:
    schedule.run_pending()
    time.sleep(30)

Answer 2

def weekday_job(x, t=None):
    week = datetime.today().weekday()
    if t is not None and week < 5:
        schedule.every().day.at(t).do(x)

weekday_job(main, '01:00')
weekday_job(main, '02:00')

while True:
    schedule.run_pending()
    time.sleep(60)

Answer 3

You can use library APScheduler. For example:

from apscheduler.schedulers.blocking import BlockingScheduler

def job_function():
    print("Hello World")

sched = BlockingScheduler()

# Runs from Monday to Friday at 5:30 (am) until
sched.add_job(job_function, 'cron', day_of_week='mon-fri', hour=5, minute=30)
sched.start()