Hi there i've been trying to adapt this to my needs but I'm just a newbe in python, I have a csv file with multiple columns and rows, important columns are 1 = old name of file, and 2 = new name of file, so I need to go the directory where the files listed in csv file are and rename them to the new name of column 2, as I say I've tried many things without success, I paste the last code I've made so you have an idea:
import os, unicodecsv as csv, sys
IDs = {}
#open and store the csv file
with open('documentos_corpus_ladino.csv','rb') as csvfile:
timeReader = csv.reader(csvfile, delimiter = ',')
# build a dictionary with the associated IDs
for row in timeReader:
IDs[ row[0] ] = row[1]
# #get the list of files
path = 'txt_orig/'
tmpPath = 'txt_tmp/'
for filename in os.listdir('txt_orig/'):
oldname = filename
newname = filename.replace(oldname, csvfile.next().rstrip().split(",")[1])
os.rename(path + filename, tmpPath + newname)
Thanks a lot.
This will rename each matching file, and report any errors trying to rename. It will not attempt to move non-existent files.
import os, unicodecsv as csv
# open and store the csv file
IDs = {}
with open('documentos_corpus_ladino.csv','rb') as csvfile:
timeReader = csv.reader(csvfile, delimiter = ',')
# build dictionary with associated IDs
for row in timeReader:
IDs[row[0]] = row[1]
# move files
path = 'txt_orig/'
tmpPath = 'txt_tmp/'
for oldname in os.listdir(path):
# ignore files in path which aren't in the csv file
if oldname in IDs:
try:
os.rename(os.path.join(path, oldname), os.path.join(tmpPath, IDs[oldname]))
except:
print 'File ' + oldname + ' could not be renamed to ' + IDs[oldname] + '!'
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