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match(pattern, string, flags=0) method returns a match object if the regex matches at the beginning of the string. Read more in our blog tutorial. The re. fullmatch(pattern, string, flags=0) method returns a match object if the regex matches the whole string.
The startswith() method returns True if a string starts with the specified prefix(string). If not, it returns False .
The startswith() string method checks whether a string starts with a particular substring. If the string starts with a specified substring, the startswith() method returns True; otherwise, the function returns False.
match() function of re in Python will search the regular expression pattern and return the first occurrence. The Python RegEx Match method checks for a match only at the beginning of the string. So, if a match is found in the first line, it returns the match object.
I have a list of files, and I want to keep only the ones which start with 'test_' and end with '.py'. I want the regex to only return the text inside the 'test_' and '.py'. I do not want .pyc files included.
I have tried:
>>>filename = 'test_foo.py'
>>>re.search(r'(?<=test_).+(?=\.py)', filename).group()
foo.py
but it still returns the extension, and will allow '.pyc' extensions (which I do not want). I'm pretty sure it's the '+' which is consuming the whole string.
This works as a fallback, but I would prefer a regex solution:
>>>filename = 'test_foo.py'
>>>result = filename.startswith('test_') and filename.endswith('.py')
>>>result = result.replace('test_', '').replace('.py', '')
>>>print result
foo
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