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In the following script I would like to pull out text between the double quotes ("). However, the python interpreter is not happy and I can't figure out why...
import re
text = 'Hello, "find.me-_/\\" please help with python regex'
pattern = r'"([A-Za-z0-9_\./\\-]*)"'
m = re.match(pattern, text)
print m.group()
The output should be find.me-/\.
741
Use the re. findall() method to extract strings between quotes, e.g. my_list = re. findall(r'"([^"]*)"', my_str) .
To extract strings in between the quotations we can use findall() method from re library.
Firstly, double quote character is nothing special in regex - it's just another character, so it doesn't need escaping from the perspective of regex. However, because Java uses double quotes to delimit String constants, if you want to create a string in Java with a double quote in it, you must escape them.
the regex looks for a quote mark " then it looks for any possible group of letters thats not " until it finds icon. and any possible group of letters that is not " it then looks for a closing "
match starts searching from the beginning of the text.
Use search instead:
#!/usr/bin/env python
import re
text = 'Hello, "find.me-_/\\" please help with python regex'
pattern = r'"([A-Za-z0-9_\./\\-]*)"'
m = re.search(pattern, text)
print m.group()
match and search return None when they fail to match.
I guess you are getting AttributeError: 'NoneType' object has no attribute 'group' from python: This is because you are assuming you will match without checking the return from re.match.
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