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Python regex : compute and replace numeric values

I have a regex issue which do not seems as common as I thought : I would like to extract all numeric values having px units, apply some calculation, and then re-inject the new value within my string. I don't want to include the px string (see exemple below), but I could use an alternative method which keep them, or change the unit type.

Exemple, multiplying values by 2.5 :

from "2px aperture 12px science 2.1px yummy cake"

I want "5 aperture 30 science 5.25 yummy cake"

I made a sketchy script, but I don't get quite the desired output :

import re
my_string = "2px aperture 12px science 2.1px yummy cake"
nb_list= re.findall(r"([0-9.]+)px", my_string)
splitted_string = re.findall('.*?px', my_string)
print(f"splitted_string = {splitted_string}")
print(f"nb_list = {nb_list}")
new_list = []
for i in range(0, len(nb_list)):
  new_n = str(float(nb_list[i])*2.5)
  new_string = re.sub(r"[0-9.]+px", new_n, splitted_string[i])
  new_list.append(new_string)
new_list = ''.join(new_list)
print(f"new_list = {new_list}")

Result :

new_list = 5.0 aperture 30.0 science 5.25

I understand why I get this result, but I don't know what to change to get the desired output.

like image 463
Arkeen Avatar asked Oct 21 '25 16:10

Arkeen


1 Answers

Just use re.sub with a callback:

r = re.sub(
    r'(\d+(\.\d+)?)px\b',
    lambda m: '{:g}'.format(float(m.group(1)) * 2.5),
    s)

It's easy to extend this to multiple units, for example:

units = {
    'px': 2.5,
    'em': 4,
}

r = re.sub(
    fr'(\d+(\.\d+)?)({"|".join(units)})\b',
    lambda m: '{:g}'.format(float(m.group(1)) * units[m.group(3)]),
    s)
like image 82
georg Avatar answered Oct 23 '25 06:10

georg



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