Python: pop from empty list

Question

I am using below line in a loop in my code

importer = exporterslist.pop(0) 

If exporterslist has no entries it returns error: IndexError: pop from empty list. How can I bypass exporterslist with no entries in it?

One idea I can think of is if exporterslist is not None then importer = exporterslist.pop(0) else get the next entry in the loop. If the idea is correct, how to code it in python?

Answer 1

You're on the right track.

if exporterslist: #if empty_list will evaluate as false.     importer = exporterslist.pop(0) else:     #Get next entry? Do something else? 

Answer 2

This one..

exporterslist.pop(0) if exporterslist else False

..is somewhat the same as the accepted answer of @nightshadequeen's just shorter:

>>> exporterslist = []    >>> exporterslist.pop(0) if exporterslist else False    False 

or maybe you could use this to get no return at all:

exporterslist.pop(0) if exporterslist else None

>>> exporterslist = []  >>> exporterslist.pop(0) if exporterslist else None >>>