Python output from print(print(print('aaa')))

Question

I don't quite understand output received from:

print(print(print('aaa')))

aaa

None

None

First aaa is clear. But I thought that second print(aaa) will throw an error as variable aaa is not defined...

Answer 1

print(print('aaa'))

The outer print will receive as argument not what inner print printed to stdout, but what inner print returned. And print function never returns anything (equivalent to returning None). That's why you see this output.

Answer 2

Here is an example which does the same thing, and you will understand it better:

def f():
    print('Hello')
print(f())

Outputs:

Hello
None

None is at the end because you are basically doing print(print('Hello')), print writes something in the python interpreter and also when you do type(print()) it outputs: <class 'NoneType'> So this part is print(None).

So that's why the output of print(print(print('aaa'))) includes None's

Answer 3

First we just split our code

>>>a = print('aaa')
aaa
>>>b = print(a)
None
>>>print(b)
None

Now you understand !! (python 3)

Answer 4

print prints on the standard output and returns None. Your second print statement gets result of first print which is None