Python one liner to substitute a list indices

Question

I want to replace those elements of list1 whose indices are stored in list indices by list2 elements. Following is the current code:

j=0
for idx in indices:
   list1[idx] = list2[j]
   j+=1

Is it possible to write a one-liner for the above four lines using lambda function or list comprehension?

EDIT
list1 contains float values
list2 contains float values
indices contain integers between 0 and len(list1)

Answer 1

Use conditional expressions,

# A test case
list1 = [0, 1, 2, 3, 4, 5, 6]
list2 = ['c', 'e', 'a']
indices = [2, 4, 0]

# Use conditional expressions
new_list = [list2[indices.index(idx)] if idx in indices else v for idx, v in enumerate(list1)] # idx2 = indices.index(idx), for list2

print(new_list)
# Output
['a', 1, 'c', 3, 'e', 5, 6]

Answer 2

Although it is not a one liner, here is an alternative that I think is more readable:

for i, v in zip(indices, list2):
    list1[i] = v