Please consider the following Python modules excerpts:
foo.py:
class Foo:
(...)
bar.py:
import foo
foo = foo.Foo()
The variable foo, which was a module object, is overwritten with a Foo object.
I know that I can use other names for the object, e.g.:
foobar = foo.Foo()
but semantically it makes more sense in my code to have it called foo, since it will be the only instance.
(I tried to workaround this by dropping classes and using modules only, but I went back to using classes because using modules only had "robustness" problems.)
This is kind of a philosophical question, but what is the "right" way of handling this potential object/module names clash?
Package and Module Names Modules should have short, all-lowercase names. Underscores can be used in the module name if it improves readability. Python packages should also have short, all-lowercase names, although the use of underscores is discouraged.
Rules for Python variables: A variable name must start with a letter or the underscore character. A variable name cannot start with a number. A variable name can only contain alpha-numeric characters and underscores (A-z, 0-9, and _ )
yes, if you define a class with the same name as an already existing class, it will override the definition. BUT existing instances of the first class will still behave as usual.
Name clashes can occur, for example, if two or more Python modules contain identifiers with the same name and are imported into the same program, as shown below: In this example, module1 and module2 are imported into the same program. Each module contains an identifier named double, which return very different results.
In my opinion there is nothing wrong with what you are currently doing, but to make it more clear for everyone reading the code I would suggest changing your code to something like the following:
import foo as foo_mod
foo = foo_mod.Foo()
Or alternatively:
from foo import Foo
foo = Foo()
This prevents the name clash so it will be more obvious that the variable foo
in your module is not going to refer to the module of the same name.
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