I have a simple problem. I need a way to make a function which generates 0s in p percent cases and 1s in all other cases. I tried doing it with random.random() like this:
p = 0.40
def generate():
x = random.random()
if x < p:
return 0
else:
return 1
However, this doesn't seem like a good way. Or it is?
Your current method is perfectly fine, you can verify this by performing a few trials with a lot of attempts. For example we would expect approximately 600000 True results with 1000000 attempts:
>>> sum(generate() for i in range(1000000))
599042
>>> sum(generate() for i in range(1000000))
599670
>>> sum(generate() for i in range(1000000))
600011
>>> sum(generate() for i in range(1000000))
599960
>>> sum(generate() for i in range(1000000))
600544
Looks about right.
As noted in comments, you can shorten your method a bit:
p = 0.40
def generate():
return random.random() >= p
If you want 1
and 0
instead of True
and False
you can use int(random.random() >= p)
, but this is almost definitely unnecessary.
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