Menu
How to get the transpose of this matrix..Any easier ,algorithmic way to do this...
1st question:
Input a=[[1,2,3],[4,5,6],[7,8,9]]
Expected output a=[[1, 4, 7], [2, 5, 8], [3, 6, 9]]
2nd Question:
Zip gives me the following output said below,how can i zip when i dont know how many elements are there in the array,in this case i know 3 elements a[0],a[1],a[2] but how can i zip a[n] elements
>>> zip(a[0],a[1],a[2])
[(1, 4, 7), (2, 5, 8), (3, 6, 9)]
396
The zip() function in Python programming is a built-in standard function that takes multiple iterables or containers as parameters. An iterable in Python is an object that you can iterate over or step through like a collection. You can use the zip() function to map the same indexes of more than one iterable.
For example X = [[1, 2], [4, 5], [3, 6]] would represent a 3x2 matrix. The first row can be selected as X[0] . And, the element in the first-row first column can be selected as X[0][0] . Transpose of a matrix is the interchanging of rows and columns.
Use the T attribute or the transpose() method to swap (= transpose) the rows and columns of DataFrame. Neither method changes an original object but returns the new object with the rows and columns swapped (= transposed object).
Use zip(*a):
>>> zip(*a)
[(1, 4, 7), (2, 5, 8), (3, 6, 9)]
How it works: zip(*a) is equal to zip(a[0], a[1], a[2]).
152
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
