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I'm refactoring a function that, given a series of endpoints that implicitly define intervals, checks if a number is included in the interval, and then return a corresponding (not related in any computable way). The code that is now handling the work is:
if p <= 100: return 0 elif p > 100 and p <= 300: return 1 elif p > 300 and p <= 500: return 2 elif p > 500 and p <= 800: return 3 elif p > 800 and p <= 1000: return 4 elif p > 1000: return 5 Which is IMO quite horrible, and lacks in that both the intervals and the return values are hardcoded. Any use of any data structure is of course possible.
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You can use the Python map() function with a String. While using the map() with a String, the latter will act like an array. You can then use the map() function as an iterator to iterate through all the string characters.
What is interval in Python? Intervals are immutable objects that can be created by specifying their connected components: >>> k = interval([0, 1], [2, 3], [10, 15]) creates an object representing the union of the mathematical intervals [0, 1], [2, 3] and [10, 15].
Python's map() is a built-in function that allows you to process and transform all the items in an iterable without using an explicit for loop, a technique commonly known as mapping. map() is useful when you need to apply a transformation function to each item in an iterable and transform them into a new iterable.
import bisect bisect.bisect_left([100,300,500,800,1000], p) here the docs: bisect
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You could try a take on this:
def check_mapping(p): mapping = [(100, 0), (300, 1), (500, 2)] # Add all your values and returns here for check, value in mapping: if p <= check: return value print check_mapping(12) print check_mapping(101) print check_mapping(303) produces:
0 1 2 As always in Python, there will be any better ways to do it.
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