Python `map` and arguments unpacking

Question

I know, that

map(function, arguments) 

is equivalent to

for argument in arguments:     function(argument) 

Is it possible to use map function to do the following?

for arg, kwargs in arguments:     function(arg, **kwargs) 

Answer 1

You can with a lambda:

map(lambda a: function(a[0], **a[1]), arguments) 

or you could use a generator expression or list comprehension, depending on what you want:

(function(a, **k) for a, k in arguments) [function(a, **k) for a, k in arguments] 

In Python 2, map() returns a list (so the list comprehension is the equivalent), in Python 3, map() is a generator (so the generator expression can replace it).

There is no built-in or standard library method that does this directly; the use case is too specialised.