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I know, that
map(function, arguments) is equivalent to
for argument in arguments: function(argument) Is it possible to use map function to do the following?
for arg, kwargs in arguments: function(arg, **kwargs) 
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Unpacking in Python refers to an operation that consists of assigning an iterable of values to a tuple (or list ) of variables in a single assignment statement. As a complement, the term packing can be used when we collect several values in a single variable using the iterable unpacking operator, * .
Use the Iterable Unpacking Operator * to Convert a Map Object Into a List in Python. In Python, the term unpacking can be defined as an operation whose primary purpose is to assign the iterable with all the values to a List or a Tuple, provided it's done in a single assignment statement.
In Python, you can unpack list , tuple , dict (dictionary) and pass its elements to function as arguments by adding * to list or tuple and ** to dictionary when calling function.
Unpacking in Python refers to assigning values in an iterable object to a tuple or list of variables for later use. We can perform unpacking by using an asterisk ( * ) before the object we would like to unpack.
You can with a lambda:
map(lambda a: function(a[0], **a[1]), arguments) or you could use a generator expression or list comprehension, depending on what you want:
(function(a, **k) for a, k in arguments) [function(a, **k) for a, k in arguments] In Python 2, map() returns a list (so the list comprehension is the equivalent), in Python 3, map() is a generator (so the generator expression can replace it).
There is no built-in or standard library method that does this directly; the use case is too specialised.
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