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Why does itertools.permutations() return a list of characters or digits for each permutation, instead of just returning a string?
For example:
>>> print([x for x in itertools.permutations('1234')]) >>> [('1', '2', '3', '4'), ('1', '2', '4', '3'), ('1', '3', '2', '4') ... ] Why doesn't it return this?
>>> ['1234', '1243', '1324' ... ] 
666
First import itertools package to implement the permutations method in python. This method takes a list as an input and returns an object list of tuples that contain all permutations in a list form.
Permutations means different orders by which elements can be arranged. The elements might be of a string, or a list, or any other data type. It is the rearrangement of items in different ways. Python has different methods inside a package called itertools, which can help us achieve python permutations.
groupby() This method calculates the keys for each element present in iterable. It returns key and iterable of grouped items.
itertools.permutations() simply works this way. It takes an arbitrary iterable as an argument, and always returns an iterator yielding tuples. It doesn't (and shouldn't) special-case strings. To get a list of strings, you can always join the tuples yourself:
list(map("".join, itertools.permutations('1234'))) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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