Python IP range to IP range match

Question

Is there any method to check if some IP addresses from a network range are present in the subnets of another IP range?

Example: 10.0.1.0/18 in 123.1.0.0/8 

If it exists, I need it to return True, else False.

Answer 1

Since Python 3.3, you can use the ipaddress module of the standard library:

from ipaddress import IPv4Address, IPv4Network

IPv4Address('192.0.2.6') in IPv4Network('192.0.2.0/28')
# True
IPv4Address('10.0.1.0') in IPv4Network('192.0.2.0/28')
# False

If you mean if the networks overlap, use overlaps:

In [14]: IPv4Network('10.0.1.0/24').overlaps(IPv4Network('192.0.2.0/28'))
Out[14]: False

Note that this module was marked as provisional in Python 3.3, but no longer is in 3.6. So enjoy it!

Answer 2

from ipaddress import ip_address, ip_network

NOTE: Other answers specifically point at IPv4Address, IPv4Network, but ip_address and ip_network simply call the IPv4 OR IPv6 version when needed.

addr = ip_address('10.0.1.0')

NOTE: the sample network you provided is not a true /8 network, so the ip_network will respond with an error of ValueError: 123.1.0.0/8 has host bits set

To get past this, by forcing the ipaddress library to essentially round down to the nearest network address, you can set strict=False and Python will find the nearest, lower address for a /8 network: 123.0.0.0

netw = ip_network('123.1.0.0/8', strict=False)

print(addr in netw)

Then it is simply a matter of testing using the in keyword.

If you want to test every address in a network range against every address in another network range, then:

net1 = ip_network('10.0.1.0/18', strict=False)
net2 = ip_network('123.1.0.0/8', strict=False)

for addr in net1:
    if addr in net2:
        print(addr, 'True')
    else:
        print(addr, 'False')

In addition, networks can be converted into sets:

n1 = set(net1)
n2 = set(net2)

And Python sets have the ability show any overlap OR inclusion (subset/superset relationships).

n1.isdisjoint(n2)
n1.issubset(n2)
n2.issubset(n1)
n2.issuperset(n1)

etc.