Lets say I have the following python source file layout:
lib/foo.py
lib/foo/bar.py
and then in my source code:
from foo import gaz
I get an import error:
ImportError: No module named foo
How can I have a .py file and a directory with the same name so I can do the following:
from foo import gaz
from foo.bar import wakawaka
The actual problem you are having, using a single import, is due to the packages having the precedence over modules:
Note that when using
from package import item
, the item can be either a submodule (or subpackage) of the package, or some other name defined in the package, like a function, class or variable. Theimport
statement first tests whether the item is defined in the package; if not, it assumes it is a module and attempts to load it. If it fails to find it, anImportError
exception is raised.
Anyway I'd strongly suggest to rename the file or the directory since you cannot import more than one module with a given name. The problem occurs because each module/package object is stored into sys.modules
, which is a simple dict
and thus it cannot contain multiple equal keys.
In particular, assuming foo.py
and the foo
directory are in different directories(and if they aren't you still can't import foo.py
), when doing:
from foo import gaz
It will load foo.py
and put the module into sys.modules
, then trying to do:
from foo.bar import wakaka
Will fail because the import tries to use the module foo.py
instead of the package.
The opposite happens if you first import foo.bar
; the imports will use the package instead of the module.
I'm pretty sure this is not something you should do, but you can force Python to import specific file as a module using imp:
import imp
with open("foo.py") as source:
foo = imp.load_module("foo", source, "./", ('', '', imp.PY_SOURCE))
now you can do:
gaz_instance = foo.gaz()
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