Python - get the full file path a function was called from?

Question

Given a module mymodule.py; and in it

def foo():
    X = # file path where foo was called from
    print(X)

How would I do what's described in the comment? Ie, if in test.py I did

from mymodule import foo
foo()

And then ran python3 test.py in the terminal, it should print the full file path of test.py

Answer 1

You could use sys.argv[0] to get the main file 's name, then you could use os.path.realpath() to get the full path of it:

import os
import sys

def foo():
    X = os.path.realpath(sys.argv[0])
    print(X)

Demo:

kevin@Arch ~> python test.py 
/home/kevin/test.py