I have a numpy
array of numbers. Below is an example:
[[-2.10044520e-04 1.72314372e-04 1.77235336e-04 -1.06613465e-04
6.76617611e-07 2.71623057e-03 -3.32789944e-05 1.44899758e-05
5.79249863e-05 4.06502549e-04 -1.35823707e-05 -4.13955189e-04
5.29862793e-05 -1.98286005e-04 -2.22829175e-04 -8.88758230e-04
5.62228710e-05 1.36249752e-05 -2.00474996e-05 -2.10090068e-05
1.00007518e+00 1.00007569e+00 -4.44597417e-05 -2.93724453e-04
1.00007513e+00 1.00007496e+00 1.00007532e+00 -1.22357142e-03
3.27903892e-06 1.00007592e+00 1.00007468e+00 1.00007558e+00
2.09869172e-05 -1.97610235e-05 1.00007529e+00 1.00007530e+00
1.00007503e+00 -2.68725642e-05 -3.00372853e-03 1.00007386e+00
1.00007443e+00 1.00007388e+00 5.86993822e-05 -8.69989983e-06
1.00007590e+00 1.00007488e+00 1.00007515e+00 8.81850779e-04
2.03875532e-05 1.00007480e+00 1.00007425e+00 1.00007517e+00
-2.44678912e-05 -4.36556267e-08 1.00007436e+00 1.00007558e+00
1.00007571e+00 -5.42990711e-04 1.45517859e-04 1.00007522e+00
1.00007469e+00 1.00007575e+00 -2.52271817e-05 -7.46339417e-05
1.00007427e+00]]
I want to know if each of the numbers is closer to 0 or 1. Is there a function in Python that could do it or do I have to do it manually?
isclose() method checks whether two values are close to each other, or not. Returns True if the values are close, otherwise False. This method uses a relative or absolute tolerance, to see if the values are close.
We can find the nearest value in the list by using the min() function. Define a function that calculates the difference between a value in the list and the given value and returns the absolute value of the result. Then call the min() function which returns the closest value to the given value.
Use a comparison operator (==) to form a comparison array. Check if all the elements in the comparison array are True.
A straightforward way:
lst=[0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9]
closerTo1 = [x >= 0.5 for x in lst]
Or you can use np:
import numpy as np
lst=[0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9]
arr = np.array(lst)
closerTo1 = arr >= 0.5
Note that >= 0.5
can be changed to > 0.5
, however you choose to treat it.
numpy.rint
is a ufunc that will round the elements of an array to the nearest integer.
>>> a = np.arange(0, 1.1, 0.1)
>>> a
array([0. , 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1. ])
>>> np.rint(a)
array([0., 0., 0., 0., 0., 0., 1., 1., 1., 1., 1.])
What if the numbers don't have to be between 0 and 1?
In that case, I'd use numpy.where
.
>>> a = np.arange(-2, 2.1, 0.1)
>>> a
array([-2.00000000e+00, -1.90000000e+00, -1.80000000e+00, -1.70000000e+00,
-1.60000000e+00, -1.50000000e+00, -1.40000000e+00, -1.30000000e+00,
-1.20000000e+00, -1.10000000e+00, -1.00000000e+00, -9.00000000e-01,
-8.00000000e-01, -7.00000000e-01, -6.00000000e-01, -5.00000000e-01,
-4.00000000e-01, -3.00000000e-01, -2.00000000e-01, -1.00000000e-01,
1.77635684e-15, 1.00000000e-01, 2.00000000e-01, 3.00000000e-01,
4.00000000e-01, 5.00000000e-01, 6.00000000e-01, 7.00000000e-01,
8.00000000e-01, 9.00000000e-01, 1.00000000e+00, 1.10000000e+00,
1.20000000e+00, 1.30000000e+00, 1.40000000e+00, 1.50000000e+00,
1.60000000e+00, 1.70000000e+00, 1.80000000e+00, 1.90000000e+00,
2.00000000e+00])
>>> np.where(a <= 0.5, 0, 1)
array([0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1])
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