Python function in background

Question

I want to run a function independently. From the function I call, I want return without waiting for the other function ending.

I tried with threadind, but this will wait, the end.

thread = threading.Thread(target=myFunc)
thread.daemon = True
thread.start()
return 'something'

Is it possible to return immediately and the other process still run? Thanks for the Answers.

EDITED The working code looks like:

 import concurrent.futures 
 executor = concurrent.futures.ThreadPoolExecutor(2) 
 executor.submit(myFunc, arg1, arg2)

Answer 1

You are more or less asking the following question:

Is it possible to run function in a subprocess without threading or writing a separate file/script

You have to change the example code from the link like this:

from multiprocessing import Process

def myFunc():
    pass  # whatever function you like

p = Process(target=myFunc)
p.start()  # start execution of myFunc() asychronously
print)'something')

p.start() is executed asychronously, i.e. 'something' is printed out immediately, no matter how time consuming the execution of myFunc() is. The script executes myFunc() and does not wait for it to finish.

Answer 2

if I understood your request correctly, you might want to take a look on worker queues https://www.djangopackages.com/grids/g/workers-queues-tasks/

Basically it's not a good idea to offload the work to thread created in view, this is usually handled by having a pool of background workers (processes, threads) and the queue for incoming requests.