I am using ftplib to connect to an ftp site. I want to get the most recently uploaded file and download it. I am able to connect to the ftp server and list the files, I also have put them in a list and got the datefield converted. Is there any function/module which can get the recent date and output the whole line from the list?
#!/usr/bin/env python
import ftplib
import os
import socket
import sys
HOST = 'test'
def main():
try:
f = ftplib.FTP(HOST)
except (socket.error, socket.gaierror), e:
print 'cannot reach to %s' % HOST
return
print "Connect to ftp server"
try:
f.login('anonymous','[email protected]')
except ftplib.error_perm:
print 'cannot login anonymously'
f.quit()
return
print "logged on to the ftp server"
data = []
f.dir(data.append)
for line in data:
datestr = ' '.join(line.split()[0:2])
orig-date = time.strptime(datestr, '%d-%m-%y %H:%M%p')
f.quit()
return
if __name__ == '__main__':
main()
RESOLVED:
data = []
f.dir(data.append)
datelist = []
filelist = []
for line in data:
col = line.split()
datestr = ' '.join(line.split()[0:2])
date = time.strptime(datestr, '%m-%d-%y %H:%M%p')
datelist.append(date)
filelist.append(col[3])
combo = zip(datelist,filelist)
who = dict(combo)
for key in sorted(who.iterkeys(), reverse=True):
print "%s: %s" % (key,who[key])
filename = who[key]
print "file to download is %s" % filename
try:
f.retrbinary('RETR %s' % filename, open(filename, 'wb').write)
except ftplib.err_perm:
print "Error: cannot read file %s" % filename
os.unlink(filename)
else:
print "***Downloaded*** %s " % filename
return
f.quit()
return
One problem, is it possible to retrieve the first element from the dictionary? what I did here is that the for loop runs only once and exits thereby giving me the first sorted value which is fine, but I don't think it is a good practice to do it in this way..
For those looking for a full solution for finding the latest file in a folder:
If your FTP server supports MLSD command, a solution is easy:
entries = list(ftp.mlsd())
entries.sort(key = lambda entry: entry[1]['modify'], reverse = True)
latest_name = entries[0][0]
print(latest_name)
If you need to rely on an obsolete LIST command, you have to parse a proprietary listing it returns.
Common *nix listing is like:
-rw-r--r-- 1 user group 4467 Mar 27 2018 file1.zip
-rw-r--r-- 1 user group 124529 Jun 18 15:31 file2.zip
With a listing like this, this code will do:
from dateutil import parser
# ...
lines = []
ftp.dir("", lines.append)
latest_time = None
latest_name = None
for line in lines:
tokens = line.split(maxsplit = 9)
time_str = tokens[5] + " " + tokens[6] + " " + tokens[7]
time = parser.parse(time_str)
if (latest_time is None) or (time > latest_time):
latest_name = tokens[8]
latest_time = time
print(latest_name)
This is a rather fragile approach.
A more reliable, but a way less efficient, is to use MDTM command to retrieve timestamps of individual files/folders:
names = ftp.nlst()
latest_time = None
latest_name = None
for name in names:
time = ftp.voidcmd("MDTM " + name)
if (latest_time is None) or (time > latest_time):
latest_name = name
latest_time = time
print(latest_name)
For an alternative version of the code, see the answer by @Paulo.
Some FTP servers support a proprietary non-standard -t switch for NLST (or LIST) command.
lines = ftp.nlst("-t")
latest_name = lines[-1]
See How to get files in FTP folder sorted by modification time.
No matter what approach you use, once you have the latest_name, you download it as any other file:
with open(latest_name, 'wb') as f:
ftp.retrbinary('RETR '+ latest_name, f.write)
Why don't you use next dir option?
ftp.dir('-t',data.append)
With this option the file listing is time ordered from newest to oldest. Then just retrieve the first file in the list to download it.
With NLST, like shown in Martin Prikryl's response,
you should use sorted method:
ftp = FTP(host="127.0.0.1", user="u",passwd="p")
ftp.cwd("/data")
file_name = sorted(ftp.nlst(), key=lambda x: ftp.voidcmd(f"MDTM {x}"))[-1]
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