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I know in python3, you can do something like:
>>> '{0} {1} {0}'.format(13, 42)
'13 42 13'
So you're using the same argument multiple times. I'd like to do the opposite. I have a sequence of numbers. I'd like to somehow print them using a single format specifier, but I don't see a way to indicate to the format syntax that a given identifier should consume the next N arguments. I can use a reduce
>>> reduce(lambda out,x: out + '{:02X}'.format(x), b'\x60\x0d\x1a\xdd', '')
'600D1ADD'
But I was hoping for a single format invocation, as I had some other characters I wanted to place around my otherwise formatted sequence.
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The format() method formats the specified value(s) and insert them inside the string's placeholder. The placeholder is defined using curly brackets: {}. Read more about the placeholders in the Placeholder section below. The format() method returns the formatted string.
A format of . 2f (note the f ) means to display the number with two digits after the decimal point. So the number 1 would display as 1.00 and the number 1.5555 would display as 1.56 .
%s is used as a placeholder for string values you want to inject into a formatted string. %d is used as a placeholder for numeric or decimal values. For example (for python 3) print ('%s is %d years old' % ('Joe', 42))
Python's str. format() method of the string class allows you to do variable substitutions and value formatting. This lets you concatenate elements together within a string through positional formatting.
What about just something like this:
list = [13, 14, 42, 43]out = ''.join([ '{0}'.format(x) for x in list ])
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