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To access the first n elements from a list, we can use the slicing syntax [ ] by passing a 0:n as an arguments to it . 0 is the start index (it is inculded).
The format for list slicing is [start:stop:step]. start is the index of the list where slicing starts. stop is the index of the list where slicing ends. step allows you to select nth item within the range start to stop.
Using Count() The python list method count() returns count of how many times an element occurs in list. So if we have the same element repeated in the list then the length of the list using len() will be same as the number of times the element is present in the list using the count(). The below program uses this logic.
list[:10]
will give you the first 10 elements of this list using slicing.
However, note, it's best not to use list as a variable identifier as it's already used by Python: list()
To find out more about these type of operations you might find this tutorial on lists helpful and the link @DarenThomas provided Explain Python's slice notation - thanks Daren)
check this
list = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]
list[0:10]
Outputs:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
The itertools module has lots of great stuff in it. So if a standard slice (as used by Levon) does not do what you want, then try the islice function:
from itertools import islice
l = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]
iterator = islice(l, 10)
for item in iterator:
print item
Use the slicing operator:
list = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]
list[:10]
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