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Is there a way, without a double loop to accomplish what the following sed command does
Input:
Time Banana spinach turkey sed -i "/Banana/ s/$/Toothpaste/" file
Output:
Time BananaToothpaste spinach turkey What I have so far is a double list which would take a long time to go through both.
List a has a bunch of numbers list b has a the same bunch of numbers but in a different order
For each entry in A i want to find the line in B with that same number and add value C to the end of it.
Hope this makes sense, even if my example doesn't.
I was doing the following in Bash and it was working however it was super slow...
for line in $(cat DATSRCLN.txt.utf8); do srch=$(echo $line | awk -F'^' '{print $1}'); rep=$(echo $line | awk -F'^' '{print $2}'); sed -i "/$(echo $srch)/ s/$/^$(echo $rep)/" tmp.1; done Thanks!
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Description. pythonsed is a full and working Python implementation of sed.
In Linux, pipes can help us to direct stdout to stdin. Therefore, we can first use the echo command to output the text to stdout and then pipe to the sed command.
Just add the line number before: sed '<line number>s/<search pattern>/<replacement string>/ . Note I use . bak after the -i flag. This will perform the change in file itself but also will create a file.
In sed , you can end a command with the flag "/i" (for example, see this other question). This seems to say "more sed commands coming," or something like that, so you can split sed commands in a script.
Using re.sub():
newstring = re.sub('(Banana)', r'\1Toothpaste', oldstring) This catches one group (between first parentheses), and replaces it by ITSELF (the \number part) followed by a desired suffix. It is needed to use r'' (raw string) so that the escape is correctly interpreted.
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