Python Equivalent of setInterval()?

Question

Does Python have a function similar to JavaScript's setInterval()?

I would like to have:

def set_interval(func, interval):     ... 

That will call func every interval time units.

Answer 1

This might be the correct snippet you were looking for:

import threading  def set_interval(func, sec):     def func_wrapper():         set_interval(func, sec)         func()     t = threading.Timer(sec, func_wrapper)     t.start()     return t 

Answer 2

This is a version where you could start and stop. It is not blocking. There is also no glitch as execution time error is not added (important for long time execution with very short interval as audio for example)

import time, threading  StartTime=time.time()  def action() :     print('action ! -> time : {:.1f}s'.format(time.time()-StartTime))   class setInterval :     def __init__(self,interval,action) :         self.interval=interval         self.action=action         self.stopEvent=threading.Event()         thread=threading.Thread(target=self.__setInterval)         thread.start()      def __setInterval(self) :         nextTime=time.time()+self.interval         while not self.stopEvent.wait(nextTime-time.time()) :             nextTime+=self.interval             self.action()      def cancel(self) :         self.stopEvent.set()  # start action every 0.6s inter=setInterval(0.6,action) print('just after setInterval -> time : {:.1f}s'.format(time.time()-StartTime))  # will stop interval in 5s t=threading.Timer(5,inter.cancel) t.start() 

Output is :

just after setInterval -> time : 0.0s action ! -> time : 0.6s action ! -> time : 1.2s action ! -> time : 1.8s action ! -> time : 2.4s action ! -> time : 3.0s action ! -> time : 3.6s action ! -> time : 4.2s action ! -> time : 4.8s