python dns.resolver get DNS record type

Question

I am learning how to use the python dns object. Quick question as I see many examples show methods of using the dns.resolver method with the DNS record type(CNAME, NS, etc). Is there a way to use this dns object to query a DNS name and pull it's resolution with the record type. Similar to what DIG supplies in the answer section.

Thanks,

Jim

Answer 1

You can get the type with rdatatype

>>> import dns.resolver
>>> answer = dns.resolver.query('google.com')
>>> rdt = dns.rdatatype.to_text(answer.rdtype)
>>> print(rdt)
A

Answer 2

Here's an example of a CNAME:

>>> cname = dns.resolver.query("mail.unixy.net", 'CNAME')
>>> for i in cname.response.answer:
...     for j in i.items:
...             print j.to_text()
... 
unixy.net.

TXT:

>>> txt = dns.resolver.query("unixy.net", 'TXT')
>>> for i in txt.response.answer:
...     for j in i.items:
...             print j.to_text()
... 
"v=spf1 ip4:..."

NS:

>>> ns = dns.resolver.query("unixy.net", 'NS')
>>> for i in ns.response.answer:
...     for j in i.items:
...             print j.to_text()
... 
ns2.unixy.net.
ns1.unixy.net.

You can get most records following the same pattern. Multiple responses queries are stored in a list. So looping is sometimes necessary (ex:multiple A and NS recs).