I don't want the file to be saved on my server, I just want the file to be read and printed out in the next page. Right now I have this.
(index.html)
<form name="fileUpload" method="post">
<input type="file" />
<input type="submit" value="Submit" />
</form>
And I'm trying to do something like this-
def upload_file(request):
if request.method == "POST":
upload = request.POST.get('fileUpload').read()
return render(request, 'directory/return.html', {'output': upload})
else:
return render(request, 'directory/index.html')
But obviously that just doesn't work. I want it to work for text files and csv files.
Thank you.
Firstly, there are some things missing in your form which you will have to add.
To upload files using a form, you’ll need to define the enctype
as "multipart/form-data"
in the <form>
element. Also, the file input element should have the name
attribute in it
index.html
<form enctype="multipart/form-data" action="/my/url/" method="post"> # define the enctype
<input type="file" name="my_uploaded_file"/> # define a 'name' attribute
<input type="submit" value="Submit" />
</form>
Then, in your views, you can access the uploaded file using request.FILES
dictionary. As per request.FILES
docs:
Each key in
FILES
is the name from the<input type="file" name="" />
. Each value inFILES
is anUploadedFile
.
You can access the uploaded file using my_uploaded_file
key in the request.FILES
dictionary.
views.py
def upload_file(request):
if request.method == "POST":
my_uploaded_file = request.FILES['my_uploaded_file'].read() # get the uploaded file
# do something with the file
# and return the result
else:
return render(request, 'directory/index.html')
Note:
request.FILES
will only contain data if the request method wasPOST
and the<form>
that posted the request has the attributeenctype="multipart/form-data"
. Otherwise,request.FILES
will be empty.
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