Python Disk-Based Dictionary

Question

I was running some dynamic programming code (trying to brute-force disprove the Collatz conjecture =P) and I was using a dict to store the lengths of the chains I had already computed. Obviously, it ran out of memory at some point. Is there any easy way to use some variant of a dict which will page parts of itself out to disk when it runs out of room? Obviously it will be slower than an in-memory dict, and it will probably end up eating my hard drive space, but this could apply to other problems that are not so futile.

I realized that a disk-based dictionary is pretty much a database, so I manually implemented one using sqlite3, but I didn't do it in any smart way and had it look up every element in the DB one at a time... it was about 300x slower.

Is the smartest way to just create my own set of dicts, keeping only one in memory at a time, and paging them out in some efficient manner?

Answer 1

The 3rd party shove module is also worth taking a look at. It's very similar to shelve in that it is a simple dict-like object, however it can store to various backends (such as file, SVN, and S3), provides optional compression, and is even threadsafe. It's a very handy module

from shove import Shove  mem_store = Shove() file_store = Shove('file://mystore')  file_store['key'] = value