python datetime remove minute and second information

Question

I have a datetime array which has hour, minute and second information. I want to remove the minute and second infromation from it and change the hour to the next hour.

i.e. peak_interval

array([datetime.datetime(2010, 12, 13, 6, 0),
       datetime.datetime(2011, 1, 12, 7, 0),
       datetime.datetime(2011, 3, 23, 16, 45),
       datetime.datetime(2011, 4, 19, 17, 15)], dtype=object)

I want to obtain the following:

peak_interval
array([datetime.datetime(2010, 12, 13, 7, 0),
       datetime.datetime(2011, 1, 12, 8, 0),
       datetime.datetime(2011, 3, 23, 17, 0),
       datetime.datetime(2011, 4, 19, 18, 0)], dtype=object)

I can write some kind of for loop but I am trying to use some smart method if possible.

Answer 1

You can easily modify just a few fields using datetime.datetime.replace

old_date = datetime.datetime(2011, 3, 23, 16, 45)
new_date = old_date.replace(minute=0, second=0, microsecond=0) + datetime.timedelta(hours=1)

Answer 2

One option is to use timedelta from datetime:

import datetime
import numpy as np
def reset(dt):
    return dt + datetime.timedelta(hours = 1, minutes = -dt.minute, seconds = -dt.second)

np.vectorize(reset)(peak_interval)

# array([datetime.datetime(2010, 12, 13, 7, 0),
#        datetime.datetime(2011, 1, 12, 8, 0),
#        datetime.datetime(2011, 3, 23, 17, 0),
#        datetime.datetime(2011, 4, 19, 18, 0)], dtype=object)