How would I create a list with values between two values I put in? For example, the following list is generated for values from 11 to 16:
list = [11, 12, 13, 14, 15, 16]
Use the range() Function to Create a List of Numbers From 1 to N. The range() function is very commonly used in Python. It returns a sequence between two numbers given in the function arguments. The starting number is 0 by default if not specified.
In Python, a list is created by placing elements inside square brackets [] , separated by commas. A list can have any number of items and they may be of different types (integer, float, string, etc.).
Use range
. In Python 2.x it returns a list so all you need is:
>>> range(11, 17) [11, 12, 13, 14, 15, 16]
In Python 3.x range
is a iterator. So, you need to convert it to a list:
>>> list(range(11, 17)) [11, 12, 13, 14, 15, 16]
Note: The second number is exclusive. So, here it needs to be 16+1
= 17
EDIT:
To respond to the question about incrementing by 0.5
, the easiest option would probably be to use numpy's arange()
and .tolist()
:
>>> import numpy as np >>> np.arange(11, 17, 0.5).tolist() [11.0, 11.5, 12.0, 12.5, 13.0, 13.5, 14.0, 14.5, 15.0, 15.5, 16.0, 16.5]
You seem to be looking for range()
:
>>> x1=11 >>> x2=16 >>> range(x1, x2+1) [11, 12, 13, 14, 15, 16] >>> list1 = range(x1, x2+1) >>> list1 [11, 12, 13, 14, 15, 16]
For incrementing by 0.5
instead of 1
, say:
>>> list2 = [x*0.5 for x in range(2*x1, 2*x2+1)] >>> list2 [11.0, 11.5, 12.0, 12.5, 13.0, 13.5, 14.0, 14.5, 15.0, 15.5, 16.0]
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