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I am currently programing in python and I created a method that inputs list from the user, without knowing whether he is multidimensional or one dimensional. how do I check? sample:
def __init__(self,target):
for i in range(len(target[0])):
w[i]=np.random.rand(len(example[0])+1)
target is the list. the problem is that target[0] might be int.
314
Look for array. shape: if it comes like (2,) means digit at first place but nothing after after comma,its 1D. Else if it comes like (2,10) means two digits with comma,its 2D.
Lists are a very widely use data structure in python. They contain a list of elements separated by comma. But sometimes lists can also contain lists within them. These are called nested lists or multidimensional lists.
Python lists are one dimensional only.
A list is identifiable by the square brackets that surround it, and individual values are separated by a comma. To get the length of a list in Python, you can use the built-in len() function. Apart from the len() function, you can also use a for loop and the length_hint() function to get the length of a list.
I think you just want isinstance ?
Example usage:
>>> a = [1, 2, 3, 4]
>>> isinstance(a, list)
True
>>> isinstance(a[0], list)
False
>>> isinstance(a[0], int)
True
>>> b = [[1,2,3], [4, 5, 6], [7, 8, 9]]
>>> isinstance(b[0], list)
True
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