I'm calling a task within a tasks in Django-Celery
Here are my tasks.
@shared_task
def post_notification(data,url):
url = "http://posttestserver.com/data/?dir=praful" # when in production, remove this line.
headers = {'content-type': 'application/json'}
requests.post(url, data=json.dumps(data), headers=headers)
@shared_task
def shipment_server(data,notification_type):
notification_obj = Notification.objects.get(name = notification_type)
server_list = ServerNotificationMapping.objects.filter(notification_name=notification_obj)
for server in server_list:
task = post_notification.delay(data,server.server_id.url)
print task.status # it prints 'Nonetype' has no attribute id
How can I call a task within a task?
I read somewhere it can be done using group
, but I'm not able to form the correct syntax. How do I do it?
I tried this
for server in server_list:
task = group(post_notification.s(data, server.server_id.url))().get()
print task.status
Throws a warning saying
TxIsolationWarning: Polling results w│
ith transaction isolation level repeatable-read within the same transacti│
on may give outdated results. Be sure to commit the transaction for each │
poll iteration. │
'Polling results with transaction isolation level '
Dont know what it is!!!
How do I solve my problem?
You are right, because each task in you for
loop will be overwrite task
variable.
You can try celery.group
like
from celery import group
and
@shared_task
def shipment_server(data,notification_type):
notification_obj = Notification.objects.get(name = notification_type)
server_list = ServerNotificationMapping.objects.filter(notification_name=notification_obj)
tasks = [post_notification.s(data, server.server_id.url) for server in server_list]
results = group(tasks)()
print results.get() # results.status() what ever you want
This should work:
celery.current_app.send_task('mymodel.tasks.mytask', args=[arg1, arg2, arg3])
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