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I have a very simple problem. This is for a pandas dataframe ("df"). The answers are all more complex regarding string compare, which I have no use for. Here is the code that works for lowercase and returns only "apple":
df2 = df1['company_name'].str.contains(("apple"), na=False) I need this to find "apple", "APPLE", "Apple", etc. Something like:
df2 = df1['company_name'].str.contains.caseignore((("apple"), na=False)) is there such a function anywhere?
Thanks.
581
Approach No 1: Python String lower() Method This is the most popular approach to case-insensitive string comparisons in Python. The lower() method converts all the characters in a string to the lowercase, making it easier to compare two strings.
Python strings are case sensitive, so these equality check methods are also case sensitive.
str. contains has a case parameter that is True by default. Set it to False to do a case insensitive match.
The equalsIgnoreCase() method compares two strings, ignoring lower case and upper case differences. This method returns true if the strings are equal, and false if not. Tip: Use the compareToIgnoreCase() method to compare two strings lexicographically, ignoring case differences.
Series.str.contains has a case parameter that is True by default. Set it to False to do a case insensitive match.
df2 = df1['company_name'].str.contains("apple", na=False, case=False) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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