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How can I get argument names and their values passed to a method as a dictionary?
I want to specify the optional and required parameters for a GET request as part of a HTTP API in order to build the URL. I'm not sure of the best way to make this pythonic.
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For non-keyworded arguments, use a single * , and for keyworded arguments, use a ** . The result would be: (1, 2) {'a': 3, 'b': 4} .
Use the Python **kwargs parameter to allow the function to accept a variable number of keyword arguments. Inside the function, the kwargs argument is a dictionary that contains all keyword arguments as its name-value pairs. Precede double stars ( ** ) to a dictionary argument to pass it to **kwargs parameter.
Hence, we conclude that Python Function Arguments and its three types of arguments to functions. These are- default, keyword, and arbitrary arguments.
To create a Python dictionary, we pass a sequence of items (entries) inside curly braces {} and separate them using a comma ( , ). Each entry consists of a key and a value, also known as a key-value pair. Note: The values can belong to any data type and they can repeat, but the keys must remain unique.
Use a single argument prefixed with **.
>>> def foo(**args): ... print(args) ... >>> foo(a=1, b=2) {'a': 1, 'b': 2} If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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