Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Python argparse : How can I get Namespace objects for argument groups separately?

I have some command line arguments categorized in groups as follows:

cmdParser = argparse.ArgumentParser()
cmdParser.add_argument('mainArg')

groupOne = cmdParser.add_argument_group('group one')
groupOne.add_argument('-optA')
groupOne.add_argument('-optB')

groupTwo = cmdParser.add_argument_group('group two')
groupTwo.add_argument('-optC')
groupTwo.add_argument('-optD')

How can I parse the above, such that I end up with three different Namespace objects?

global_args - containing all the arguments not part of any group
groupOne_args - containing all the arguments in groupOne
groupTwo_args - containing all the arguments in groupTwo

Thank you!

like image 585
shikhanshu Avatar asked Aug 10 '16 22:08

shikhanshu


People also ask

How are arguments optional in Argparse?

To add an optional argument, simply omit the required parameter in add_argument() . args = parser. parse_args()if args.

What is Store_true in Python?

The store_true option automatically creates a default value of False. Likewise, store_false will default to True when the command-line argument is not present.

What does parse_args return?

Adding arguments Later, calling parse_args() will return an object with two attributes, integers and accumulate . The integers attribute will be a list of one or more ints, and the accumulate attribute will be either the sum() function, if --sum was specified at the command line, or the max() function if it was not.


2 Answers

you can do it in this way:

import argparse
parser = argparse.ArgumentParser()

group1 = parser.add_argument_group('group1')
group1.add_argument('--test1', help="test1")

group2 = parser.add_argument_group('group2')
group2.add_argument('--test2', help="test2")

args = parser.parse_args('--test1 one --test2 two'.split())

arg_groups={}

for group in parser._action_groups:
    group_dict={a.dest:getattr(args,a.dest,None) for a in group._group_actions}
    arg_groups[group.title]=argparse.Namespace(**group_dict)

This will give you the normal args, plus dictionary arg_groups containing namespaces for each of the added groups.

(Adapted from this answer)

like image 70
Ignacio Avatar answered Oct 23 '22 08:10

Ignacio


Nothing in argparse is designed to do that.

For what it's worth, the parser starts off with two argument groups, one that displays as positionals and the other as optionals (I forget the exact titles). So in your example there will actually be 4 groups.

The parser only uses argument groups when formatting the help. For parsing all arguments are put in a master parser._actions list. And during parsing the parser only passes around one namespace object.

You could define separate parsers, with different sets of arguments, and call each with parse_known_args. That works better with optionals (flagged) arguments than with positionals. And it fragments your help.

I have explored in other SO questions a novel Namespace class that could nest values based on some sort of dotted dest (names like group1.optA, group2.optC, etc). I don't recall whether I had to customize the Action classes or not.

The basic point is that when saving a value to the namespace, a parser, or actually a Action (argument) object does:

setattr(namespace, dest, value)

That (and getattr/hasattr) is all that the parser expects of the namespace. The default Namespace class is simple, little more than a plain object subclass. But it could be more elaborate.

like image 35
hpaulj Avatar answered Oct 23 '22 07:10

hpaulj