Python-Appending to a list in a dictionary

Question

I've been attempting to add a value to the end of a list inside a dictionary using a different dictionary. The assignment is a little more complicated, so I have simplified the problem down to these three lines, but keep getting None as a result.

finley = {'a':0, 'b':2, 'c':[41,51,61]}
crazy_sauce = {'d':3}
print finley['c'].append(crazy_sauce['d'])

Answer 1

Your code is fine but print finley['c'].append(crazy_sauce['d']) prints none since finley['c'].append(crazy_sauce['d']) returns none. you remove print here and add a print finley['c'] in next line

finley = {'a':0, 'b':2, 'c':[41,51,61]}
crazy_sauce = {'d':3}
finley['c'].append(crazy_sauce['d'])
print finley['c']

Answer 2

You are attempting to print the return value of the .append() function, which is None. You need to print the dict value after the call to .append(), like so:

finley      = {'a':0, 'b':2, 'c':[41, 51 ,61]}
crazy_sauce = {'d':3}

finley['c'].append(crazy_sauce['d'])

print(finley['c'])

Where the output is the following list:

[41, 51, 61, 3]

Answer 3

Your solution is correct, but :

Most functions, methods that change the items of sequence/mapping does return None: list.sort, list.append, dict.clear.

So just use print dict in next line after you update the list in dict.

finley = {'a':0, 'b':2, 'c':[41,51,61]}
crazy_sauce = {'d':3}
finley['c'].append(crazy_sauce['d'])
print(finley)