I have a 60000 by 200 numpy array. I want to make it 60000 by 201 by adding a column of 1's to the right. (so every row is [prev, 1]) Concatenate with axis = 1 doesn't work because it seems like concatenate requires all input arrays to have the same dimension. How should I do this? I can't find any existing useful answer, and most of the answers about this were written a few years ago so things might be different now.
Use the append() Function to Append Values to a 2D Array in Python.
Add array element You can add a NumPy array element by using the append() method of the NumPy module. The values will be appended at the end of the array and a new ndarray will be returned with new and old values as shown above.
NumPy's concatenate function can be used to concatenate two arrays either row-wise or column-wise. Concatenate function can take two or more arrays of the same shape and by default it concatenates row-wise i.e. axis=0. The resulting array after row-wise concatenation is of the shape 6 x 3, i.e. 6 rows and 3 columns.
Let me just throw in a very simple example with much smaller size. The principle should be the same.
a = np.zeros((6,2))
array([[ 0., 0.],
[ 0., 0.],
[ 0., 0.],
[ 0., 0.],
[ 0., 0.],
[ 0., 0.]])
b = np.ones((6,1))
array([[ 1.],
[ 1.],
[ 1.],
[ 1.],
[ 1.],
[ 1.]])
np.hstack((a,b))
array([[ 0., 0., 1.],
[ 0., 0., 1.],
[ 0., 0., 1.],
[ 0., 0., 1.],
[ 0., 0., 1.],
[ 0., 0., 1.]])
Using numpy index trick to append a 1D vector to a 2D array
a = np.zeros((6,2))
# array([[ 0., 0.],
# [ 0., 0.],
# [ 0., 0.],
# [ 0., 0.],
# [ 0., 0.],
# [ 0., 0.]])
b = np.ones(6) # or np.ones((6,1))
#array([1., 1., 1., 1., 1., 1.])
np.c_[a,b]
# array([[0., 0., 1.],
# [0., 0., 1.],
# [0., 0., 1.],
# [0., 0., 1.],
# [0., 0., 1.],
# [0., 0., 1.]])
Under cover all the stack
variants (including append
and insert
) end up doing a concatenate
. They just precede it with some sort of array reshape.
In [60]: A = np.arange(12).reshape(3,4)
In [61]: np.concatenate([A, np.ones((A.shape[0],1),dtype=A.dtype)], axis=1)
Out[61]:
array([[ 0, 1, 2, 3, 1],
[ 4, 5, 6, 7, 1],
[ 8, 9, 10, 11, 1]])
Here I made a (3,1) array of 1s, to match the (3,4) array. If I wanted to add a new row, I'd make a (1,4) array.
While the variations are handy, if you are learning, you should become familiar with concatenate
and the various ways of constructing arrays that match in number of dimensions and necessary shapes.
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