Python 3.6 pathlib Path change name parent directory

Question

The new Path package from the pathlib library, which has been added from Python 3.4, seems a powerful replacement of approaches such as os.path.join(), but I've some trouble working with it.

I have a path that can be anything from folder_foo/file.csv to long/path/to/folder_foo/file.csv. I read the .csv file in folder_foo with pandas, modify it and want to save it to folder_bar/file.csv or long/path/to/folder_bar/file.csv.

Essentially I want to rename folder_foo to folder_bar in the Path object.

EDIT: example path code

csv_path = Path("long/path/to/folder_foo/file.csv")

Attempts

1

csv_path.parents[0] = csv_path.parents[0] + "_clean")

Which leads to the error TypeError: unsupported operand type(s) for +: 'PosixPath' and 'str', which means you cannot use + to combine a PosixPath with a str as described in TypeError: unsupported operand type(s) for +: 'PosixPath' and 'str'.

2

To solve this I tried the following:

csv_path.parents[0] = Path(str(csv_path.parents[0]) + "_clean")

Which however results in the error : TypeError: '_PathParents' object does not support item assignment.

Since PosixPath is not a list, this error is understandable.

3

Maybe .parts is a better approach, but

csv_path.parts[-2] = csv_path.parts[-2][:-3] + "bar"

results in: TypeError: 'tuple' object does not support item assignment.

Question

How can I easily rename the file's parent folder?

Answer 1

Would rather split this up for readability:

bar_folder = csv_path.parent.parent / 'folder_bar'
csv_path2 = bar_folder / csv_path.name

Having the destination folder as a variable also enables you to create the folder using for example:

bar_folder.mkdir(exist_ok=True)