>>> '{:0.10}'.format(1/3)
'0.3333333333'
>>> '{:0.10}'.format(100/3)
'33.33333333'
The first gives 10 digits after the decimal point, the second gives 8. Does "precision" mean total digits? How do I control significant digits after the decimal point only?
Double precision numbers have 53 bits (16 digits) of precision and regular floats have 24 bits (8 digits) of precision. The floating point type in Python uses double precision to store the values.
In Python, to print 2 decimal places we will use str. format() with “{:. 2f}” as string and float as a number. Call print and it will print the float with 2 decimal places.
Using “%”:- “%” operator is used to format as well as set precision in python. This is similar to “printf” statement in C programming.
You need to include the type f
(for float) to control the number of digits after the decimal place:
>>> '{:.10f}'.format(100/3)
'33.3333333333'
Without specifying the type, Python falls back to the general number type and the number is rounded to the specified number of significant digits. From the documentation:
The precision is a decimal number indicating how many digits should be displayed after the decimal point for a floating point value formatted with 'f' and 'F', or before and after the decimal point for a floating point value formatted with 'g' or 'G'.
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